Let the length of the billboard `L =20 m` be in the x direction and the width of the billboard `l =10 m` be in the y direction.

The special theory of relativity finds that if we have two inertial systems
S and S' where **S' is moving relative to S with the speed V in the
X direction** the longitudinal (along x) dimension is contracting and
the perpendicular dimensions stay the same if we measure the dimensions in the
same system (S or S').

Therefore if a traveller (system S') is moving with a speed V parallel to
the billboard length (in the positive x direction) then the billboard (system
S) as seen by the traveller will have

`L' =L*sqrt(1-V^2/C^2)`

`l' =l`

where `C =3*10^8 m/s` is the speed of light in vacuum.

From first relation above we have

`1 -V^2/C^2 = (L')/L`

`V^2/C^2 =1-10/20 =0.5`

`V = C*sqrt(0.5) =0.707*C =0.707*3*10^8 =2.121*10^8 m/s`

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