According to the following balanced reaction, how many moles of NO are formed from 12.66 moles of NO2 if there is plenty of water present? 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g)

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The given balanced chemical reaction is:

3 NO2 (g) + H2O (l) -> 2 HNO3 (aq) + NO (g)

In this reaction, nitrogen dioxide (NO2) reacts with water (H2O) to form nitric acid (HNO3) and nitric oxide (NO).

Using stoichiometry, 3 moles of nitrogen dioxide reacts with 1 mole of water to form 2 moles of nitric acid and 1 mole of nitric oxide.

In other words, if plenty of water is present, 3 moles of nitrogen dioxide will form 1 mole of nitric oxide. It also means that each mole of nitrogen dioxide will form 1/3 moles of nitric oxide.

In this case, 12.66 moles of nitrogen dioxide is present.

Hence, the number of moles of nitric oxide formed are:

12.66 moles x 1/3 = 4.22 moles.

Thus, using this balanced chemical reaction, we can say that if 12.66 moles of NO2 react with plenty of water, 4.22 moles of NO are formed.

Hope this helps.

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