**Find x .Determine x if |3x+6|=9 .**

It is given that |3x+6|=9

As the absolute value of 3x + 6 is equal to 9 either 3x + 6 = 9 or -(3x + 6) = 9

3x + 6 = 9

=> 3x = 3

=> x = 1

-(3x + 6) = 9

=> 3x + 6 = -9

=> 3x = -15

=> x = -5

**The solutions of x are x = 1 and x = -5**

**Find x .Determine x if |3x+6|=9 .**

What you have to do is solve for two possible equations. They are

3x + 6 = 9

and

-(3x + 6) = 9 which is the same as

-3x - 6 = 9

So you must solve both:

3x + 6 = 9

3x = 3

**x = 1**

-3x - 6 = 9

-3x = 15

**x = -5**

**So the answer for this is x = -5,1**

**Finding xDetermine x if |3x+6|=9.**

We have to solve |3x+6|=9

As the absolute value of (3x + 6) is equal to 9, the actual value of 3x + 6 can be 9 or -9.

This gives 3x + 6 = 9

=> x = 3/3 = 1

and 3x + 6 = -9

=> 3x = -15

=> x = -5

**The required values of x are x = 1 and x = -5.**

**Finding xDetermine x if |3x+6|=9.**

To solve this, you need to split your first equation into two equations. This is because |3x+6| can equal 3x + 6 or it can equal -(3x+6) which is -3x - 6.

So you need to solve two equations: 3x + 6 = 9 and -3x - 6 = 9.

Now it's simple:

3x + 6 = 9

3x = 3

x = 1

-3x - 6 = 9

-3x = 15

x = -5

**So the answer is that x = -5,1**

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