The shopper pushes the cart with a force of 15 N. The cart is loaded to make its mass equal to 31 kg. The cart starts from rest.

The force applied results in an acceleration given by a = force/mass. The distance moved by an object starting from rest and with an acceleration a in t seconds is given by (1/2)*a*t^2

For a force of 15 N, the acceleration is a = 15/31

In 4.3 s the distance moved D = (1/2)*(15/31)*(4.3)^2

=> 4.47 m

The mass of a child weighing 88 N is 88/9.8. If the child is placed in the cart the mass of the cart becomes 31 + 88/9.8 kg.

The distance moved by the cart in 4.3 seconds in this case is (1/2)*(15/(31+88/9.8))*4.3^2

=> (1/2)*0.3751*4.3^2

=> 3.46 m

**In 4.3 seconds the cart moves 4.47 m when it is loaded and the child is not placed in it. And it moves 3.46 m when the child is placed in it.**

## See eNotes Ad-Free

Start your **48-hour free trial** to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.

Already a member? Log in here.