`y = -x^2 + 1, y=0` Use the shell method to set up and evaluate the integral that gives the volume of the solid generated by revolving the plane region about the y-axis.

Expert Answers

An illustration of the letter 'A' in a speech bubbles

To be able to use the shell method, a a rectangular strip from the bounded plane region should be parallel to the axis of revolution.

By revolving multiple rectangular strip, it forms infinite numbers of hollow pipes or representative cylinders.


 In this method, we follow the formula: `V = int_a^b` (length * height * thickness)

or `V = int_a^b 2pi` * radius*height*thickness


radius `(r)` = distance of the rectangular strip to the axis of revolution

height `(h)` = length of the rectangular strip

thickness = width  of the rectangular strip  as `dx` or `dy` .

For the bounded region, as shown on the attached image, the rectangular strip is parallel to y-axis (axis of rotation). We can a let:


`h=f(x) or h=y_(above)-y_(below)`

`h = -x^2+1 -0`

`h = -x^2+1`

thickness `= dx` with boundary values from `a=0` to `b=1` .

Plug-in the values on `V = int_a^b 2pi` * radius*height*thickness , we get:

`V = int_0^1 2pi*x*(-x^2+1)*dx`

`V =int_0^1 2pi(-x^3+x)dx`

Apply basic integration property:` intc*f(x) dx = c int f(x) dx` and

`int (u+v) dx=int (u) dx+ int (v) dx` .

`V = 2pi int_0^1 (-x^3+x)dx`

`V = 2pi[ int_0^1 (-x^3)dx +int_0^1 (x)dx]`

Apply power rule for integration: `int x^n dy= x^(n+1)/(n+1)`

`V = 2pi[ -x^(3+1)/(3+1) + x^(1+1)/(1+1)]|_0^1`

`V = 2pi[ -x^4/4 + x^2/2]|_0^1`

Apply definite integration formula: `int_a^b f(y) dy= F(b)-F(a)` .

`V = 2pi[ -(1)^4/4 + (1)^2/2] -2pi[ -(0)^4/4 + (0)^2/2]`

`V =2pi[-1/4+1/2]-2pi[0+0]`

`V =2pi[1/4]-2pi[0]`

`V =pi/2-0`

`V =pi/2 ` or `1.57 ` (approximated value)

See eNotes Ad-Free

Start your 48-hour free trial to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.

Get 48 Hours Free Access
Image (1 of 1)
Approved by eNotes Editorial