**Note:- If y = sinx ; then dy/dx = cosx**

**If y = cosx ; then dy/dx = -sinx**

**2sinx*cosx = sin(2x)**

Now,

`y = (sinx)^2`

`or, y = sin^2x`

differentiating

`y' = 2sinx*cosx`

`or,y' = sin(2x)`

differentiating

`y'' = 2cos(2x)`

` `

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