To find the y-intercept, substitute in 0 for x and solve for y.

`-3(0)+y=15`

Multiply `-3` by each term inside the parentheses.

`0+y=15`

`y` -intercept: `(0,15)`

What is the y-intercept of the line `-3x+y = 15` ?

To find the y-intercept algebraically, rewrite the equation in slope-intercept form, `y = mx + b` , where `m` represents the slope and `b` represents the y-intercept.

`-3x + y = 15`

`-3x+3x + y = 15 + 3x`

`y = 3x + 15`

**The y-intercept is (0, 15).**

The intercepts of a line are the points where the line intersects the coordinate axes. The y-intercept is a point where the line intersects y-axis. The x-coordinate of this point is 0.

Since the x-coordinate is 0, the y-intercept can be found by plugging in x = 0 into the equation of the line:

`-3x+y = 15`

`-3*0 + y = 15`

`0 + y = 15`

y = 15.

The y-inercept of this line is the point with the coordinates (0, 15). See the graph below:

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