What is the equation of a line that passes through the point (6, 0) and the distance between this point and where it touches the y axis is 10.

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The line passes through the point (6, 0). This is the x-intercept. The y- intercept is (0, y1). As the distance between (6, 0) and the point (6, 0) is 10:

6^2 + y^2 = 10^2

=> y^2 = 100 - 36 = 64

y = 8 and y = -8

There are two two lines that satisfy the given condition with y-intercepts y = 8 and y = -8.

The equation of the two lines is: x/6 + y/8 = 1 and x/6 - y/8 = 1

=> 8x + 6y = 48 and 8x - 6y = 48

The required equation of the line is 8x + 6y = 48 and 8x - 6y = 48

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