Use the point slope form line equation y+4=-4(x-2).  what point does this line pass through. Rewrite this equation in slope-intercept form. What is the x-intercept of this line.

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The slope of a line is defined as the change in y divided by the change in x:


Given a point `(x_1,y_1)`, the change in y can be written as


And the change in x can be written as:


The equation of the line can then be written:


In `y-(-4)=-4(x-2)` the point `(x_1,y_1)` is equal to (2,-4) and the slope is equal to -4.

Therefore the line passes through the point (2,-4) and this point is the basis of this equation.

The slope intercept form is y=mx+b, where m is the slope and b is the y intercept. To write the slope intercept method, solve for y.



`y=-4x+4`             (1)

Thus the slope is -4 and the y intercept is 4.

The standard form of a line is: ax+by=c. Add 4x to both sides of (1).


To determine the x intercept, substitute 0 for y.



Thus the x intercept is 1.


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The equation of the line y + 4 = -4*(x - 2) is in the point slope form. Rewriting the equation `(y+4)/(x - 2) = -4` . The slope of this line is -4 and it passes through the point (2, -4).

y + 4 = -4*(x - 2)

=> y + 4 = -4x + 8

=> y = -4x + 4

This is the equation in the slope-intercept form.

At the x-intercept the y-coordinate is 0.

0 = -4x + 4

=> x = 1

The x-intercept of the line is 1.

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