There is a leak in the Rein's roof. This leak must be fixed by the time the 500th tain drop falls through the roof. The leak allows 2 drops to go through the roof on the 1st day, 4 drops through on the second day, 8 drops through on the third day, and so on. On what day will the 500th drop fall through the roof

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I agree with the 7.97.  I checked my Excel table and saw an error.  I attached a correct table here.  It shows during the 8th day.  Sorry.

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In the problem, the number of drops for the first three days are 2, 4, and 8.

Notice that the number of drops forms a sequence. So, our next step is to determine if it is an arithmetic or geometric sequence. Since 2, 4 and 8 are all divisible by 2, then it is possible that this is a geometric sequence. To verify, determine if the consecutive numbers have common ratio.

To do so, apply the formula:

`r =a_n/a_(n-1)`

`r=a_3/a_2 =8/4=2`


Since the value of r's are the same, hence, the number of drops form a geometric sequence.

That means, to determine nth day when 500th rain drops on the leak, apply the formula of sum of geometric sequence.

`S_n=(a_1(1 - r^n))/(1-r)`

So, plug-in `S_n=500` , `a_1=2`  and `r=2` .


Then, simplify the equation.






And, take the natural logarithm of both sides to remove the n in the exponent.

`ln 251=ln2^n`




Rounding off to the nearest whole number, the value of n becomes:


Hence, the 500th rain drops on the 8th day.

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