# The systolic blood pressures of women aged 18 to 24 are normally distributed with a mean of 120.3 and a standard deviation of 12.7. What is the systolic blood pressure interval for the central 90% of all women between the ages of 18 to 24?

We are given that the mean systolic blood pressure of a population (women aged 18 to 24) is `mu=120.3` and the standard deviation of this distribution is `sigma=12.7`. We are also told that the distribution is normal. We are asked to find the interval that contains the middle 90% of women aged 18–24.

A normal distribution is symmetric about the mean. This means that there is reflexive symmetry about the central point. The standard normal distribution has a mean of zero and a standard deviation of 1. Normal distributions can be converted to the standard normal distribution (normalized) by converting the data to z-values.

If 90% of the population is in the interval, 10% lie outside the interval; 5% below the interval and 5% above, by symmetry. In the standard normal distribution, the z-score that corresponds to 5% below is `z~~-1.65`. We can get this value from a standard normal table (you will find that .0500 lies between -1.64 and -1.65) or using some utility. My calculator returns -1.644853626. This number comes from the function that describes the normal or Gaussian distribution.

In a similar fashion, we find the z-score with 95% of the population above it is about 1.65.

We use these values to find the data points in the actual distribution.

If z=-1.65, then `x=z(sigma)+mu~~-1.65(12.7)+120.3=99.3`,

and if z=1.65, then `x=1.65(12.7)+120.3~~141.3`. (This means that a systolic reading of 99.3 lies 1.65 standard deviations below the mean and represents the bottom 5% of the population.)

The interval for the middle 90% is 99.3<x<141.3

## See eNotes Ad-Free

Start your 48-hour free trial to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.