sketch the graphs of y=cos2x & y=-0.5 over the domain-pi<_x<_pi use algebraic method to determine values of x where the graphs intersect.   

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`y = cos(2x)` and `y= -1/2`

Let's find the general solution in `-piltxltpi ` .


`cos(2x) = -1/2`

The primary solution for `(2x)` is,

`2x = cos^(-1)(-1/2)`

`(2x) = (2pi)/3`


The general solution for `cos(2x)` is given by,

`2x = 2npi+-(2pi)/3`

`x = npi+-pi/3` where `n in Z` .


For n= -1,

`x = -pi+-pi/3 `

The solution in the given range is `-pi+pi/3 = (-2pi)/3`


For n = 0,

`x = +-pi/3,`

The solutions in teh given range are, `pi/3` and `(-pi)/3` .


For n= 1,

`x = pi+-pi/3`

The solution in teh given range is,

x = pi-pi/3 = (2pi)/3


Therefore the solutions for x  in the given range are,

`x = (-2pi)/3` ,` x = (-pi)/3` ,` x =pi/3` and `x = (2pi)/3`


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