Student Question

Determine a fourth-degree Taylor polynomial matching the function `e^x` at `x_0=1` .

Expert Answers

An illustration of the letter 'A' in a speech bubbles

The formula for the Taylor polynomial of degree `n` centered at `x_0` , approximating a function `f(x)` possessing `n` derivatives at `x_0` , is given by

`p_n(x)=f(x_0)+f'(x_0)(x-x_0)+f''(x_0)/(2!)(x-x_0)^2+f'''(x_0)/(3!)(x-x_0)^3+...`

`p_n(x)=sum_(j=0)^n (f^((j))(x_0))/(j!) (x-x_0)^j`

For `f(x)=e^x, f^((j))(2)=e^2` for all `j` .

Therefore to fourth order in `x` about the point `x_0=2`

`e^x~~p_4(x)=e^2+e^2(x-2)+e^2/2(x-2)^2+e^2/(3!)(x-2)^3+e^2/(4!)(x-2)^4`

Notice the graph below. The function `p_4(x)~~e^x` (red) the most at `x=2` . It will become more and more approximate to `e^x` the higher order the approximation.

See eNotes Ad-Free

Start your 48-hour free trial to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.

Get 48 Hours Free Access
Approved by eNotes Editorial