i have done a small mistake there, x should be minus,

`x = -21.5 degrees`

The general solution for sine is

`x = 180n+(-1)^n (-21.5)`

here n is any integer,

n = 0 you get, `x = -21.5`

n = 1, you get `x = 180+21.5 = 201.5`

n =2, you get `x = 360 - 21.5 = 338.5`

So the answers in 0<x<360 are 201.5 and 338.5

As above, the quadratic yields the solution of `sinx=(1-sqrt(3))/2`

`sin^(-1)((1-sqrt(3))/2)~~-21.5^@`

For x between 0 and 360 degrees the angles will be :

`~~180+21.5=201.5` or `~~360-21.5=338.5`

(The reference angle is 21.5 degrees, and sin is negative in the third and fourth quadrant)

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