# The length of a rectangular garden is 2 feet longer than 3 times its width. If the perimeter of the garden is 100 feetfind the width and the length of the garden

Let the length of the rectangle be L, and the width be W.

Given that the length is 2 ft longer than 3 times w.

Then we write: L = 2 + 3w...........(1)

Also, given that the perimeter is 100 ft.

==> P = 2L + 2W = 100

We will divide by 2.

==> L + W = 50 ........(2).

Now we will solve the system by substitution.

==> 2+3W + W = 50

==> 2 + 4W = 50

==> Subtract 2 from both sides.

==> 4W = 48

Now divide by 4.

==> W = 48/4 = 12

==> L = 2+ 3w = 2+ 3*12 = 2+36 = 38

Then the width is 12 ft and the length is 38 ft.

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The length of a rectangular garden is 2 feet longer than 3 times its width. The perimeter of the garden is 100 feet.

We have to find the width and the length of the garden.

The perimeter of a rectangle with length L and width W is given by 2*(L + W)

Here length = 2 + 3* width

=> L = 2 + 3W

The perimeter = 2L + 2W = 100

=> 2(2 + 3W) + 2W = 100

=> 4 + 6W + 2W = 100

=> 8W = 96

=> W = 12

L = 2 + 3*12 = 2 + 36 = 38

The length of the garden is 38 feet and the width is 12 feet.