The known condition:

`1/x` -`1/y` =4

`(3x+5xy-3y)/(x-3xy-y)` =?

Expert Answers

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First, multiply the given condition by the LCD which is xy.

`xy*(1/x - 1/y)=4*xy`

`y-x = 4xy`

Then, plug-in this to


But before substituting, group together the 3x and 3y in the numerator. And in the denominator group x and y too.

`=(5xy + (3x-3y))/(-3xy+(x-y))`

Factor out the GCF in 3x-3y.


To express (x-y) as (y-x), factor out the negative.



Then, plug-in y-x =4xy.





Hence, `(3x+5xy-3y)/(x-3xy-y)=1` .

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