You should keep the term `3sqrt(2(bsqrt2 + 5)) ` to the left side and you need to move the terms -2b and `sqrt18` to the right side, such that:

`3sqrt(2(bsqrt2 + 5)) = 2b - sqrt18`

You should raise to square both sides, such that:

`9(2(bsqrt2 + 5)) = (2b - sqrt18)^2`

You should notice that `sqrt18 = 3sqrt2` , hence, you may substitute `3sqrt2` for `sqrt18` , such that:

`18(bsqrt2 + 5) = 4b^2 - 12bsqrt2 + 18`

Opening the brackets, yields:

`18bsqrt2 + 90 = 4b^2 - 12bsqrt2 + 18`

`4b^2 - 12bsqrt2 + 18 - 18bsqrt2- 90 = 0`

`4b^2 - 30bsqrt2 - 72 = 0`

You should divide by 2 such that:

`2b^2 - 15bsqrt2 - 36 = 0`

You should use quadratic formula such that:

`b_(1,2) = (15+-sqrt(225 + 288))/4`

`b_(1,2) = (15+-3sqrt57)/4`

**Hence, evaluating the solutions to the given equation yields
`b_(1,2) = (15+-3sqrt57)/4` .**

## See eNotes Ad-Free

Start your **48-hour free trial** to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.

Already a member? Log in here.