The coordinates of the centroid of a triangle with vertices at `(x_1, y_1)` ,`(x_2, y_2)` and `(x_3, y_3)` are given by `((x_1+x_2+x_3)/3, (y_1+y_2+y_3)/3)`

For the triangle ABC with vertices A(-3,-4) B(-5,6) and C (7,4) the centroid lies at: `((-3 - 5 + 7)/3, (-4 + 6 + 4)/3)` or `(1/3, 2)`

**The centroid of the triangle lies at** `(1/3, 2)`

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