How do you divide 2/3 by 7/9?

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To divide by a fraction, flip the fraction and multiply.

`2/3 * 9/7`


Cancel the common factor of 3 in the denominator of the first term `2/3` and the numerator of the second term `9/7`

`2/3 * (9^3)/7`


Reduce the expression by removing the common factor of 3 in the denominator of the first term `2/3` and the numerator of the second term `9/7`

`2 * 3/7`


Multiply 2 by 3 to get 6.

` 6/7`

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To divide fractions, multiply by the reciprocal of the divisor, the second fraction.

`2/3-: 7/9`

` ` `2/3* 9/7`

` `Multiply numerators and denominators, then simplify.

`(2*9)/(3*7) = 18/21`

Now simplify by dividing both numerator and denominator by greatest common facor, 3.

`18/21 = 6/7`

The solution is `6/7.`

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Dividing by fraction `a/b` is the same as multiplying by reciprocal value of that fraction `b/a.`  

`a/b:c/d=a/b*d/c`

So in your case you have

`2/3:7/9=2/3*9/7=(2*9)/(3*7)=18/21`

If we divide both numerator and denominator by 3 we get

`6/7` <--Your solution

The other way to do this is to write this as a double fraction

`(2/3)/(7/9)`

Now, to get numerator you multiply the outer numbers and to get denominator you multiply the inner numbers. Of course your result is the same `6/7.`

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