Given a point `(x_1,y_1)` and a slope m the equation of theline is `y-y_1=m(x-x_1)`

So the equation is `y-7=-3(x-(-3/4))`

`y-7=-3(x+3/4)` in point-slope form.

We can solve for y to get the equation in slope-intercept form:

`y=-3x-9/4+7`

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**`y=-3x+19/4` in slope-intercept form.**

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Then we can put into standard form:

`4y=-12x+19`

`12x+4y=19` in standard form.

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