This function is defined on entire `RR` and is infinitely differentiable. The necessary condition of extremum for such a function is `f'(x) = 0.`

The derivative of `f(x)` is

`sinh(x-1) + xcosh(x-1) - sinh(x-1) =xcosh(x-1).`

The only solution of the equation `f'(x) = 0` is `x = 0,` because `cosh(x) gt 0` for all `x.` Moreover, this fact gives us that `f'(x)` is positive for positive `x` and negative for negative `x,` so `f(x)` decreases on `(-oo, 0)` and increases on `(0, +oo).`

Therefore `x = 0` is the point where a **local minimum** is
reached. The value of the function at this point is `-cosh(-1) = -(e + 1/e)/2
approx -1.543.`

## See eNotes Ad-Free

Start your **48-hour free trial** to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.

Already a member? Log in here.