`f(x) = cosh(8x+1)` Find the derivative of the function

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`f(x)=cosh(8x+ 1)`

Take note that the derivative formula of cosh is

`d/dx[cosh(u)] = sinh(u) *(du)/dx`

Applying this formula, the derivative of the function will be

`f'(x) = d/dx [cosh(8x+1)]`

`f'(x) = sinh(8x + 1)*d/dx(8x+1)`

`f'(x)=sinh(8x + 1) * 8`

`f'(x) = 8sinh(8x +1)`

 

Therefore, the derivative of the function is `f'(x) =8sinh(8x+1)` .

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