Carlos attends art class every 4 weeks, chess club every 2 weeks, and fencing lessons every 3 weeks. If he attended all three this week, when will he attend all three again?

 

 

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Denote the minimum number of weeks after which Carlos will attend all three classes during one week as `N.` Our task is to find that `N.`

The next art classes will be after `4` weeks since now, then after `4+4=8` weeks since now and, in general, after `4*A` weeks since now, where `A` is any natural number.

For chess club the formula is `2*C,` and for fencing lessons the formula is `3*F.`

And all these events will happen simultaneously after `N` weeks, i.e. all these numbers, `4A,` `2C` and `3F,` must be equal to `N:`

`4A = 2C = 3F = N.`

We see that `4,` `2` and `3` are divisors of `N,` and `N,` in turn, is a multiple of `4,` `2` and `3.` This means `N` is a common multiple of `4,` `2` and `3,` and we are interested in the least common multiple, `N=LCM(4,2,3).`

Let's find `N=LCM(4,2,3) = LCM(2^2, 2^1, 3^1).`

It must contain all prime factors from `4,` `2` and `3,` they are `2` and `3.` And `2` must be at the power `2` to make a multiple of `4.` The result is  `2^2*3=12.`

Thus the event in interest will happen after 12 weeks first (and will happen again after each next 12 weeks).

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