Calculus II

Image (1 of 1)

Expert Answers

An illustration of the letter 'A' in a speech bubbles

First we need to calculate intersection points. This we can determine from these two equations









Also since `x(t_1)=-2` and `x(t_2)=2` it's easy to see that area under `y=4` (this is simple to calculate because it is actually square) is `4cdot(2-(-2))=16.`  If we subtract area under the other curve  we will get area between the curves.

And since area under parametrically defined curve `x=f(t),` `y=g(t)`  is given by formula


we have





` ` `8-6ln3` <--Your solution

Area between the curves is equal to `8-6ln3.`

See eNotes Ad-Free

Start your 48-hour free trial to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.

Get 48 Hours Free Access
Image (1 of 1)
Approved by eNotes Editorial