What constant acceleration is required to increase the speed of a car from 26 mi/h to 56 mi/h in 5 s?

What constant acceleration is required to increase the speed of a car from 26 mi/h to 56 mi/h in 5 s? (Round your answer to two decimal places.)

_____________ft/s^2

Expert Answers

An illustration of the letter 'A' in a speech bubbles

Start by stating your necessary unit conversions:

`1 hr = 3600 s`

`1mi=5280 ft`

The required formula to calculate acceleration is:

`a = (v2 - v1) / t`

where, `a = `acceleration, `v2 = ` final speed, `v1 = ` initial speed, and `t = time`

` ``v1 = 26` mi/h `* 1/3600`h/s `* 5280` ft/mi

`= 38.13 ft/s`

`v2 = 56 ` mi/h `*1/3600` h/s `*5280` ft/mi

`= 82.13 ft/s`

and finally, we know that `t = 5s`

We substitute our values and solve:

`a = (82.13-38.13)/5`

`= 8.80` `ft/s^2`

`:.` The constant acceleration will be `8.80 ft/s^2.`

Approved by eNotes Editorial
An illustration of the letter 'A' in a speech bubbles

The value of the acceleration of the car over a duration of 5 seconds in terms of ft/s^2 to increase the speed from 26 miles/hr to 56 miles/hr has to be determined.

First convert the given speeds to ft/s.

26 miles/hr = 38.13 ft/s and 56 miles/hr = 82.13 ft/s.

The value of the acceleration is (82.12 - 38.13)/5 = 44/5 = 8.8 ft/s^2

An acceleration of 8.8 ft/s^2 is required to increase the speed from 26 mi/hr to 56 mi/hr in 5 s.

See eNotes Ad-Free

Start your 48-hour free trial to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.

Get 48 Hours Free Access
Approved by eNotes Editorial