-8v-10=-3(2v-2)

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To determine the value of v in the given equation, we must apply the distibutive property of multiplication to the right side of the equation first. This gives

`-8v-10=-3(2v-2)`

`-8v-10=-6v+6`

Then if group like terms, we have

`-8v+6v=6+10`

`-2v=16`

`v=-8`

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You need to solve for variable v the given linear equation, hence, you first need to perform the multiplication to the right side, such that:

`-8v - 10 = -6v + 6`

You need to isolate the terms that contain the variable v to the left side, such that:

`-8v + 6v = 10 + 6 => -2v = 16 => v = 16/(-2) => v = -8`

Hence, evaluating the variable v, yields `v = -8.`

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