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This is a system of three equations with three variables and can be solved by substitution.

`4a+4b-c=-4`      (1)

`5a+2b+c=-8`     (2)

`8a-4b-4c=-10`  (3)

Solve (1) for c.

`c=4a+4b+4`        (4)

Substitute (4) for c in (2) and simplify.



`3a+2b=-4`           (5)

Substitute (4) for c in (3) and simplify.



`-8a-20b=6`        (6)

Solve the system of two equations (5) and (6) with two variables by elimination.  Multiply (5) by 10 and add to (6).





Solve for a.


Substitute `-17/11` for a in (6).


Solve for b.



Substitute `-17/11` for a and `7/22` for b in (4).


Verify by substituting `-17/11` for a, `7/22` for b and `-10/11` for c in (2).





Thus a=1.55, b=0.32 and c=-0.91

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