`1/3+1/5+1/7+1/9+1/11+...` Confirm that the Integral Test can be applied to the series. Then use the Integral Test to determine the convergence or divergence of the series.

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The series can be written as,


Based on the above pattern we can write the series as,


The integral test is applicable if f is positive, continuous and decreasing function on the interval `[k,oo)` where `k>=1` and `a_n=f(x)` . Then the series converges or diverges if and only if the improper integral `int_k^oof(x)dx` converges or diverges.

For the given series `a_n=1/(2n+1)`

Consider `f(x)=1/(2x+1)`

Refer to the attached graph of the function. From the graph we can see that the function is positive, continuous and decreasing on the interval `[1,oo)`

We can also determine whether function is decreasing by finding the derivative f'(x) such that `f'(x)<0` for `x>=1`

We can apply the integral test, as the function satisfies the conditions for the integral test.

Now let's determine whether the corresponding improper integral `int_1^oo1/(2x+1)dx` converges or diverges.


Let's first evaluate the indefinite integral `int1/(2x+1)dx`

Apply integral substitution:`u=2x+1`



Take the constant out and use common integral:`int1/xdx=ln|x|`


Substitute back `u=2x+1`

`=1/2ln|2x+1|+C`  where C is a constant





Since the integral `int_1^oo1/(2x+1)dx` diverges, we conclude from the integral test that the series diverges.

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