The density of water is given in terms of mass/volume and is equal to 1g/mL or 1 kg/L.

The mass of 5000 mL or 5 L or water is 5 kg or 5000 g.

The given solution contains 0.065 g of sulfur dioxide dissolved in 5 L of water. Looking at the mass of water and that of sulfur dioxide we have 0.065 g of sulfur dioxide dissolved in 5000 g of water.

To find the part per million of sulfur dioxide we divide 0.065 by 5000.

0.065/5000 = 1.3*10^-5 = 13*10^-6

Therefore we have 13 parts per million of sulfur dioxide in the given solution.

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