Verify if the value of the limit of the function f(x)=(x^2-6x+5)/(x-1) is 4

x-->1

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We have to verify the value of lim x--> 1[ (x^2 - 6x +  5)/(x - 1)]

Substituting x = 1 we get the indeterminate form 0/0.

So, we can use l'Hopital's rule and substitute the numerator and denominator by their derivatives.

=> lim x--> 1[ (2x - 6)/1]

Substitute x = 1

=> 2 - 6

=> -4

The value of lim x--> 1[ (x^2 - 6x +  5)/(x - 1)] is not 4 but -4.

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