thilinag
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Recent Activity

Answered a Question in Math
The first derivative, `f'(x) = 4*x^34*3*x^2+0 = 4x^312x^2=4(x^33x^2)` At critical points, `f'(x) = 0` `4(x^33x^2) = 0` `x^2(x3) = 0` This gives, `x = 0 or x = 3` At `x = 0, f(x) = 2` and, at... 
Answered a Question in Math
First derivative to locate the x coordinates of critical points. `f'(x) = 3*x^23*2*x+0 = 3x^26x ` At critical points, `f'(x) = 0,` `3x^26x = 0` `x^22x=0` `x(x2) =0` This gives, `x = 0 or x... 
Answered a Question in Math
`f = x^2+3x8` First derivative to find the locations of extreme points, `f' = 2*x+30 = 2x+3` At extremes points, `f' = 0, 2x+3 = 0` therefore, `x = 3/2` Now, we know that there is an extreme... 
Answered a Question in Math
`f = 6x x^2` `f' = 62*x` `f' = 2(3x)` At extrema, f'=0, this give `3 x = 0 therefore x =3 ` At x = 3, there is a local extreme point. At x = 3, `f = 6*33^2 = 189 = 9` Second derivative... 
Answered a Question in Math
See the attached MATLAB and it shows that there is a maximum and a minimum within that range. We can find the x values of these extreme points by solving the derivative of the function. >> f...
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