kellimartin
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Answered a Question in Math
The quadratic formula is x= b + sqr root(bsquared  4ac) all divided by 2a. In part a) a=3, b=1 and c=2 so, [1 (+) sqr root(1squared  4*3*(2))]/(2*3) gives x= [1 (+) sqr root (1+24)]/6... 
Answered a Question in Math
When numbers are in proportion to each and in reduced form, then at some point they had to have a number in common that would then reduce to 3/4. Consider this number x. So, before it was reduced,... 
Answered a Question in Math
They are not like binomials, so they don't just cancel. Factor out a 1 on top to get 1(2x6)/(2x6). Then you can simplify to 1. 
Answered a Question in Math
Use the determinant b(squared)  4ac if it is>0 then 2 real solutions if it =0 then 1 real solution if it<0 2 imaginary solutions a)(12)(squared)  4(4)(9) = 0 so: 1 real b)5(squared) ... 
Answered a Question in Math
The function will have imaginary roots when the determinant is negative. The determinant = (b(squared)4ac so: 12(squared)  4(k)(9)<0 14436k<0 36k<144 k>4
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