`z = w^(3/2) (w + ce^w)` Differentiate.

Textbook Question

Chapter 3, 3.2 - Problem 20 - Calculus: Early Transcendentals (7th Edition, James Stewart).
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balajia | College Teacher | (Level 1) eNoter

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`z(w)=w^(5/2)+cw^(3/2)e^w`

`z'(w)=(5/2)w^(3/2)+c(e^w(3/2)w^(1/2)+e^ww^(3/2))`

`z'(w)=sqrtw(w((5/2)+ce^w)+(3/2)ce^w)`

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