# You need to make an aqueous solution of 0.181 M calcium acetate for an experiment in lab, using a 250 mL volumetric flask. How much solid calcium acetate should you add? In grams.

To solve this problem we can apply the formula in getting the molarity of the solution. We know that:

`Molarity = (mol es)/(Liters of Solution)`

and moles of any compound can be represented as:

`Mol es = (given mass)/(molar mass)`

Now the problem is asking for the given mass...

Start your 48-hour free trial to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

To solve this problem we can apply the formula in getting the molarity of the solution. We know that:

`Molarity = (mol es)/(Liters of Solution)`

and moles of any compound can be represented as:

`Mol es = (given mass)/(molar mass)`

Now the problem is asking for the given mass or the mass needed to create 0.181 M calcium acetate.

First, we have to get the moles of calcium acetate using the formula of the molarity:

`Molarity = (mol es)/(Liters of Solution)`

`Mol es = Molarity * Liters of solution`

`Mol es = (0.181) * (0.25)`

Moles = 0.04525 moles of calcium acetate

Then we can get the given mass:

`Mol es = (given mass)/(molar mass)`

`Given mass = Mol es of calcium ace tate * Molar mass`

`Given mass = (0.04525)*(158.17)`

Given mass = 7.16 grams calcium acetate - final answer