In a triangle, any 2 sides must be less than the sum of the third side and more than the difference.
The 2 sides given have a sum of 109 and a difference of 1.
Therefore, `1 < x+7 < 109`
To solve: `1 lt x + 7` or `x +...
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In a triangle, any 2 sides must be less than the sum of the third side and more than the difference.
The 2 sides given have a sum of 109 and a difference of 1.
Therefore, `1 < x+7 < 109`
To solve: `1 lt x + 7` or `x + 7 lt 109`
`-6 < x` or `x < 102`
The solution is x can be any value between -6 and 107 or `-6<x<107.`