In a triangle, any 2 sides must be less than the sum of the third side and more than the difference.

The 2 sides given have a sum of 109 and a difference of 1.

Therefore, `1 < x+7 < 109`

To solve: `1 lt x + 7` or `x +...

## See

This Answer NowStart your **48-hour free trial** to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Already a member? Log in here.

In a triangle, any 2 sides must be less than the sum of the third side and more than the difference.

The 2 sides given have a sum of 109 and a difference of 1.

Therefore, `1 < x+7 < 109`

To solve: `1 lt x + 7` or `x + 7 lt 109`

`-6 < x` or `x < 102`

**The solution is x can be any value between -6 and 107 or `-6<x<107.` **