# You collect 6.36 moles of hydrogen gas from your lab experiment involving the decomposition of water by electrolysis. The pressure inside your rigid collection vessel is at 1.00 atm. Another lab group adds their collected gas to yours, giving it an additional 1.28 moles. What is the new pressure inside the container?

t-nez | Certified Educator

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The number of moles of a gas is directly proportional to the pressure of the gas at constant temperature and volume.

This comes from the ideal gas law:

PV=nRT or PV/nT = R, a constant

We can assume constant volume because the container is rigid, and there's no indication that the temperature changed.

When V and T are unchanged they can be left out of the equation so P/n equals a constant. When pressure and number of moles change, P1/n1 = P2/n2.

We can rearrange this to solve for the new pressure: P2 = (P1)(n2)/n1

P1 = 1.00 atm

n1 = 6.36 moles

n2 = 6.36 moles + 1.28 moles = 7.64 moles

P2 = (1.00 atm)(7.64 mol)/(6.36 mol) = 1.20 atm

This answer is consistent with what we expect, a higher pressure because the number of moles of gas increased.

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## Related Questions

sandaruwanisubasingha | Student

we can solve this  problem with ideal gas equation, which is pv=nRT

where, p=pressure of the container

v=volume of the container

n=number of moles of the gas

R= Universal gas constant

T= temperature in kelvin

If we substitute the values in the first instant in to the equation;(that is before adding the second volume of gas)

1x v =6.36x Rx T----(1)

If we substitute the second  set of values( that is after the addition of second gas sample)

p2x v = (6.36+1.28) x Rx T----(2)

note:  * since the question doesn't say about a change of temperature

we can assume that  the temperature is constant

* Container is said to be  rigid so we can assume  that the   volume is             constant.

Divide equation number (1) by (2)

(1x v =6.36x Rx T)  ----(1)

____________________

(p2x v = 7.64x Rx T)----(2)

By simplifying these equations  you would get

6.36p2 =7.64

p2       = 7.64/6.36

=1.20 atm//