1 Answer | Add Yours
This is differential equation with separated variables.
Now we integrate whole equation.
`int dy/(y-1)=int cotx dx`
`ln(y-1)=ln (sin x)+ln C=ln(C sin x)`
Hence your function (or set of functions to be exact) is
`y(x)=1+Csin x` where `C in RR.`
We’ve answered 319,863 questions. We can answer yours, too.Ask a question