# `y = x + tan(x), (pi, pi)` Find an equation of the tangent line to the curve at the given point.

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Student Comments

balajia | Student

The slope of the tangent is equal to the derivative of the equation of the curve at the given point.

`dy/dx = 1+sec^2x`

Slope of the tangent is equal to 2

The equation of the tangent is equal to y-pi=2(x-pi)

That is

`2x-y-pi=0. `

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