`y = x + cot(x)` Find the derivative of the trigonometric function.

1 Answer

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hkj1385 | (Level 1) Assistant Educator

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Note:- 1) If y = cotx ; then dy/dx = -cosec^2(x)

2) If y = x^n ; where 'n' = constant ; then dy/dx = n*x^(n-1)

Now, 

`y = x+cot(x)`

`dy/dx = y' = 1 - cosec^2(x)`

`or, dy/dx = -[cosec^2(x) - 1]`

`or, dy/dx = y' = -cot^2(x)`

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