`y = x^2 ln(2x)` Find y' and y''.

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  Find y' and y''.

For the first derivative, use the product rule AB'+BA'.  

Be warned that since we have a ln(2x) term, we will need to use chain rule, which is the derivative of the inner term 2x.

`y' = x^2* (1/(2x)) * 2 + ln(2x) *2x`

Simplify the above equation.

The first derivative is:  `y'=x + 2xln(2x)`

To find the second derivative, we will...

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