`y = (x^2 - 1)/(x^2 + x + 1) , (1, 0)` Find an equation of the tangent line to the given curve at the specified point.
The slope of the tangent at a point is equal to the derivative of the given function at that point.
By substituting (1,0) we get the derivative of the function which is equal to slope of the tangent at (1,0).
The slope is equal to 2/3.
The equation of the tangent is y-0=(2/3)(x-1)
that is 2x-3y-2=0.