`y = tan(x), y = 2sin(x), (-pi/3)<=x<=(pi/3)` Sketch the region enclosed by the given curves and find its area.

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`y=tan(x) , y=2sin(x), -pi/3<=x<=pi/3`

Refer the attached image. Graph of y=tan(x) is plotted in blue color and graph of y=2sin(x) is plotted in red color.

Area of the region enclosed by the given curves(A)=`2int_0^(pi/3)(2sin(x)-tan(x))dx` (by symmetry)






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