`y = (t^2 + 2)/(t^4 - 3t + 1)` Differentiate.

balajia | Student

`y(t)=(t^2+2)/(t^4-3t+1)`

`y'(t)=(2t(t^4-3t+1)-(4t^3-3)(t^2+2))/(t^4-3t+1)^2`

`y'(t)=(-2t^5-8t^3-3t^2+2t+6)/(t^4-3t+1)^2`

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