`y = sqrt(x + sqrt(x + sqrt(x)))` Find the derivative of the function.

3 Answers

gsarora17's profile pic

gsarora17 | (Level 2) Associate Educator

Posted on


`y'=(1/(2sqrt(x+sqrt(x+sqrt(x))))) *d/dx (x+sqrt(x+sqrt(x)))`

`y'=(1/(2sqrt(x+sqrt(x+sqrt(x))))) *(1+d/dxsqrt(x+sqrt(x)))` 

`y'=(1/(2sqrt(x+sqrt(x+sqrt(x))))) *(1+(1/(2sqrt(x+sqrt(x)))*d/dx (x+sqrt(x))))`

`y'=(1/(2sqrt(x+sqrt(x+sqrt(x))))) *(1+(1/(2sqrt(x+sqrt(x))))*(1+d/dxsqrt(x)))`

`y'=(1/(2sqrt(x+sqrt(x+sqrt(x))))) *(1+(1/(2sqrt(x+sqrt(x)))) *(1+1/(2sqrt(x))))`

`y'=(1/(2sqrt(x+sqrt(x+sqrt(x))))) *(1+(1/(2sqrt(x+sqrt(x)))) *((2sqrt(x)+1)/(2sqrt(x))))`

`y'=(1/(2sqrt(x+sqrt(x+sqrt(x))))) *(1+(2sqrt(x)+1)/(4sqrt(x)sqrt(x+sqrt(x))))`

`y'=(1/(2sqrt(x+sqrt(x+sqrt(x))))) *((4sqrt(x)sqrt(x+sqrt(x))+2sqrt(x)+1)/(4sqrt(x)sqrt(x+sqrt(x))))`


hkj1385's profile pic

hkj1385 | (Level 1) Assistant Educator

Posted on

Note:- 1) If y = sqrt(x) ; then dy/dx = 1/2sqrt(x)


y = sqrt[x + sqrt{(x) + sqrt(x)}]

Apply, the chain rule i.e ,

if y = u*v ; where u & v  botyh are functions of 'x' ; then

dy/dx = u*(dv/dx) + v*(du/dx)

Also, apply the rule of outer to inner when there are subfunctions inside a function.

Please find the solution in the attachment.

This image has been Flagged as inappropriate Click to unflag
Image (1 of 1)

1 reply Hide Replies

balajia's profile pic

balajia | College Teacher | (Level 1) eNoter

Posted on