`y = sqrt(x) + 1/sqrt(x)` Find the limit, if possible
This function is defined for x>0.
When x tends to +0, sqrt(x) tends to 0 and 1/sqrt(x) tends to +infinity, and y tends to +infinity.
The same answer for x tending to infinity.
And for x tending to any finite positive value the limit is y at this value, because y is continuous.