`y = sinx , y = 0 , x = 0 , x = pi` Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis.
The region bounded by `y=sin(x)` , `y =0` , `x=0` ,and `x=pi ` revolved about the x-axis is shown on the attached image. We may apply Disk Method wherein we use a rectangular strip representation such that it is perpendicular to the axis of rotation.
The vertical orientation of the rectangular strip shows the thickness of strip =dx.
That will be the basis to use the formula of the Disc method in a form of:
`V = int_a^b A(x) dx ` where `A(x) = pir^2` and` r =y_(above)-y_(below)` .
The `r` is radius of the disc which is the same as the length of the rectangular strip.
Then,` r = sin(x)=0 = sin(x)` with boundary values of x from` x=0 ` to `x=pi.`
The integral will be:
`V = int_0^pi (sin(x))^2 dx`
`V = x/2-(sin(x)cos(x))/2|_0^pi`
Using the definite integral formula: `int_a^b f(x) dx = F(b) - F(a)` , we get:
`V =[pi/2-(sin(pi)cos(pi))/2] -[0/2-(sin(0)cos(0))/2]`
`V = [pi/2-(0*(-1))/2] -[0-(0*1)/2]`
`V = [pi/2-0]-[0-0]`
`V = pi/2`