`y = sin(x), 0<=x<=pi` Use a graph to give a rough estimate of the area of the region that lies beneath the given curve. Then find the exact area.
Refer the graph in the attached image.
From the graph it appears that the area is `~~` 2/3 of the rectangle.
Area of the region= `~~` 2/3(Area of rectangle)
Area of the region =`~~2/3(pi*1)=2/3*3.14=2.09`
Actual Area of the region=`int_0^pisin(x)dx`