`y = sin(tan(2x))` Find the derivative of the function.

Expert Answers
hkj1385 eNotes educator| Certified Educator

Note:- 1)If y = sin(ax) ; then dy/dx = a*cos(ax)

2) If y = tan(ax) ; then dy/dx = a*sec^2(ax)

Thus,

y = sin(tan(2x))

dy/dx = y' = cos(tan(2x))*[sec^2(2x)]*2

or, dy/dx = y' = 2*cos(tan(2x))*[sec^2(2x)]