`y = sin(tan(2x))` Find the derivative of the function.

Textbook Question

Chapter 3, 3.4 - Problem 31 - Calculus: Early Transcendentals (7th Edition, James Stewart).
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hkj1385 | (Level 1) Assistant Educator

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Note:- 1)If y = sin(ax) ; then dy/dx = a*cos(ax)

2) If y = tan(ax) ; then dy/dx = a*sec^2(ax)

Thus,

y = sin(tan(2x))

dy/dx = y' = cos(tan(2x))*[sec^2(2x)]*2

or, dy/dx = y' = 2*cos(tan(2x))*[sec^2(2x)]

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