`y = sin(sin(x)), (pi, 0)` Find an equation of the tangent line to the curve at the given point.
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growley52
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`y = pi - x` is the exact answer.
At `x = pi` ``
`y = sin(sin(pi)) = sin(0) = 0`
`y' = 1/2 (cos(x - sin(x)) + cos(x + sin(x))) = 1/2(cos(pi) + cos (pi))`
=-1. So y = -x + pi, using the slope intercept form.
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