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Using d/dx (sin x) = cos x . d/dx (x) = cos x
`y' = d/dx sin(sin(sin x)) = cos(sin(sinx)) * d/dx (sin(sinx))`
`= cos(sin(sin x)) * cos(sin x) d/dx (sin x)`
`= cos(sin(sin x)) * cos(sin x) * cos x`
hope this helps.
It can be solved by method of derivation by substitution.
Image uploaded gives detailed solution.
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